南阳理工ACM1076–方案数量

题目地址：http://acm.nyist.net/JudgeOnline/problem.php?pid=1076

分析：

<span style="font-size:18px;">#include <stdio.h>int main()
{
    long long a[32][32];
    int i,j;
    int m,n;
    a[0][0]=0;
    for (i=1;i<32;i++)
    {
        a[0][i]=1;
        a[i][0]=1;
    }
    for (i=1;i<32;i++)
    {
        for (j=1;j<32;j++)
        {
            a[i][j] = a[i][j-1]+a[i-1][j];
        }    }
    while (scanf("%d%d",&m,&n)!=EOF&&(m!=0||n!=0))
        printf("%lld\n",a[m][n]);
    return 0;
}
        </span>