[LeetCode]题解（python）：082 – Remove Duplicates from Sorted List II

题目来源

https://leetcode.com/problems/remove-duplicates-from-sorted-list-ii/

Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.

For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.

题意分析

Input:

:type head: ListNode

Output:

:rtype: ListNode

Conditions:与83题不同，只要元素出现过，则将该元素去掉

题目思路

因为list是有序的，并且可能返回一个空list，所以增加一个头节点。再增加一个节点时，就看这个节点之后是否有值与这个节点的值重复，如果有就不加这个值的【所有】节点

AC代码（Python）

 # Definition for singly-linked list.
 # class ListNode(object):
 #     def __init__(self, x):
 #         self.val = x
 #         self.next = None class Solution(object):
     def deleteDuplicates(self, head):
         """
         :type head: ListNode
         :rtype: ListNode
         """
         if head == None or head.next == None:
             return head         ans = ListNode(-1)
         ans.next = head
         p = ans
         temp = p.next         while p.next:
             while temp.next and temp.next.val == p.next.val:
                 temp = temp.next
             if p.next == temp:
                 p = p.next
                 temp = p.next
             else:
                 p.next = temp.next         return ans.next