LeetCode刷题：第一题 两数之和

代码如下：

 /**
  * Note: The returned array must be malloced, assume caller calls free().
  */
 int* twoSum(int* nums, int numsSize, int target) {
     static int a[] = {};     for (int i = ; i < numsSize; i++) {
         for (int j = i + ; j < numsSize; j++) {
             if (nums[i] + nums[j] == target) {
                 a[] = i;
                 a[] = j;
                 return a;
             }
         }
     }
     return ;
 }

这道题简单，就不做过多解释。

而另一种方法，则是用到基数排序

 /*************************************************************************
     > File Name: 1-1.cpp
     > Author: Mr.Lee
     > Mail: 18646139976@163.com
     > Created Time: 五  5/10 11:10:39 2019
  ************************************************************************/ void radix_sort(int *arr, int *main_ind, int n) {
     #define MAX_N 65536
     #define MAX_M 32768
     #define L(x) (x & 0xffff)
     #define H(x) ((x >> 16) & 0xffff)     int cnt[MAX_N] = {}, *p;
     int *temp = (int *)malloc(sizeof(int) * n);
     int *ind = (int *)malloc(sizeof(int) * n);
     for (int i = ; i < n; i++) cnt[L(arr[i])] += ;
     for (int i = ; i < MAX_N; i++) cnt[i] += cnt[i - ];
     for (int i = n - ; i >= ; i--) {
         temp[--(cnt[L(arr[i])])] = arr[i];
         ind[cnt[L(arr[i])]] = i;
     }
     memset(cnt, , sizeof(cnt));
     for (int i = ; i < n; i++) cnt[H(temp[i])] += ;
     for (int i = MAX_M; i < MAX_M + MAX_N; i++) cnt[i % MAX_N] += cnt[(i - ) % MAX_N];
     for (int i = n - ; i >= ; i--) {
         arr[--cnt[H(temp[i])]] = temp[i];
         main_ind[cnt[H(temp[i])]] = ind[i];
     }
     free(temp);
     free(ind);
     return;
 } int *twoSum(int *nums, int numsSize, int target, int *returnSize) {
     int *ind = (int *)malloc(sizeof(int) * numsSize);
     radix_sort(nums, ind, numsSize);
     int p = , q = numsSize - ;
     while (nums[p] + nums[q] != target) {
         if (nums[p] + nums[q] > target) --q;
         else ++p;
     }
     int *ret = (int *)malloc(sizeof(int) * );
     ret[] = ind[p];
     ret[] = ind[q];
     if (ret[] > ret[]) {
         ret[] ^= ret[], ret[] ^= ret[], ret[] ^= ret[];
     }
     free(ind);
     returnSize[] = ;
     return ret;
 }

还有一种方法，则是哈希表

/*************************************************************************
    > File Name: 1-2.cpp
    > Author: Mr.Lee
    > Mail: 18646139976@163.com
    > Created Time: 五  5/10 11:30:27 2019
 ************************************************************************/typedef struct Data {
    int val, ind;
}typedef struct HashTable {
    Data *data;
    int *flag;
    int size;
} HashTable;HashTable *init(int n) {
    HashTable *h = (HashTable *)malloc(sizeof(HashTable));
    h->data = (Data *)malloc(sizeof(Data) * n);
    h->flag = (int *)calloc(sizeof(int), (n /  + ) );
    h->size = n;
    return h;
}int hash(int val) {
    return val & 0x7fffffff;
}int check(HashTable *h, int ind) {
    int x = ind / , y = ind % ;
    return (h->flag[x] & (1LL << y)) != ;
}void set(HashTable *h, int ind, Data d) {
    int x = ind / , y = ind % ;
    h->data[ind] = d;
    h->flag[x] |= (1LL << y);
    return;
}void insert(HashTable *h, int ind, Data d) {
    Data d = {val, val_ind};
    int ind = hash(val) % h->size;
    int time = ;
    while (check(h, ind)) {
        ind += (time * time);
        ind %= h->size;
    }
    set(h, ind, d);
    return;
}int query(HashTable *h, int val) {
    int ind = hash(val) % h->size;
    int time = ;
    while (check(h, ind) && h->data[ind].val != val) {
        ind += (time * time);
        ind %= h->size;
    }
    if (check(h, ind)) return h->data[ind].ind;
    return -;
}void clear(HashTable *h) {
    if (h == NULL) return;
    free(h->data);
    free(h->flag);
    free(h);
    return;
}int *twoSum(int *nums, int numsSize, int target, int *returnSize) {
    HashTable *h = init(numsSize * );
    int *ret = (int *)malloc(sizeof(int) * );
    for (int i = , ind; i < numsSize; i++) {
        if ((ind = query(h, target - nums[i])) == -) {
            insert(h, nums[i], i);
            continue;
        }
        ret[] = ind;
        ret[] = i;
        break;
    }
    returnSize[] = ;
    return ret;
}