Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2
, return 1->2
.
Given 1->1->2->3->3
, return 1->2->3
.
题解:水题不解释
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *deleteDuplicates(ListNode *head) {
ListNode *p = head;
while(p != NULL){
while(p->next != NULL && p->next->val == p->val){
ListNode* temp = p->next;
p->next = p->next->next;
delete(temp);
}
if(p!=NULL)
p = p->next;
}
return head;
}
};
Java版本:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public ListNode deleteDuplicates(ListNode head) {
if(head == null)
return head;
ListNode current = head;
ListNode next = current.next;
while(next != null){
if(current.val == next.val){
//删除next指向的节点
current.next = next.next;
next = current.next;
}else {
current = next;
}
}
return head;
}
}